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Sample Case: An invoice for $600 is dated January 10, 1973 and is paid on January 20. Terms are specified as 2/10, n/60—anticipation allowance is 6% . Determine the following:
  Amount of 2/10 Discount
  Invoice Balance Remaining (Net Difference)
  Amount of Anticipation Discount
  Net Invoice Amount
Solution
 Enter:  See Displayed:  
 
600 SAVE  2 %   $
  12.00
  2/10 discount
 
   $
  588.00
  balance (net difference)
 
6 % 50 × 360 ÷   $
  4.90
  anticipation discount
 
   $
  583.10
  net invoice amount

Statistical Analysis

Mean, Standard Deviation
This calculation finds the mean (arithmetic average) and standard deviation (measure of dispersion around the mean). Options are provided to enable you to interact with and modify results by adding new data or correcting data entry errors. In addition, the number of entries and sum of the squares can be obtained. Information is entered as follows:
1 Press   CLx (CLEAR) to assure the HP-80 is clear of previous data.
2 Key in values successively until all are entered; press Σ+ after each entry  . To correct an incorrect value before it is loaded with the Σ+ keystroke, press CLx. After the value is loaded, correct by reentering incorrect value, press   Σ+ (Σ–), enter correct value, press Σ+ and continue entering values. The last Σ+ pressed provides the sum of all entries.
3 Press   to obtain mean.
4 Press x y to obtain standard deviation. If there are more values to be entered, go to step 5.
5 Press x y again.
6 Press     ( Σ), go to step 2.
   Data values must be keyed in manually prior to each Σ+ keystroke; they cannot be generated through intermediate calculations or RCL operations.
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