WP-34S: Speed of y^x

[Marcel Samek]

I have been playing around with benchmarking certain operations and I came across the odd fact that 1.01 ^ 1.01 executes more than twice as fast 2 ^ 2 (both using the y^x operator).

I am curious as to why that is.

[Paul Dale]

I don't have the sources to hand due to a computer crash, but I suspect this is related to the calculation of log used in this function. LN(2) is likely slower than LN(1.01). If it isn't that e^x would be my next suspect.

- Pauli