I have a simple program for the 42s that uses the solver to work out the value for the diameter of an object or area depending on what the user chooses (see below).

What I would like to know, is there a way to also include the circumference while using the solver. For example if 7.3 was chosen for the "Dia" then if you pressed the key corresponding to "Area" it would work out 41.85 or if you pressed the key corresponding to "Circ" you would get 22.93.

I'm not sure if this can be done but would be greatful if someone out there can help.

Thanks

Mike

{41-Byte Prgm}

LBL "Dia"

MVAR "Dia"

MVAR "Area"

RCL "Dia"

x2

PI

X

4

/

RCL- "Area"

END