uRCL* on HP15C

[Csaba Tizedes (Hungary)]

We were talking about HP15C matrix operations and we sadly noticed that there are no uRCL* instructions on the machine.
Is there some trick to solve this with one operation?
Thanks for any idea!

(Our Google group link is: Calculator (Számológép) Group and the topic of HP15C discussions: [link:https://groups.google.com/forum/?hl=hu&fromgroups=#!topic/szamologep/Fs1UrDM6JWo[126-150-false]]discussion HP15C programming (page 6)[/link]

[Thomas Klemm]

Quote:

---

Is there some trick to solve this with one operation?

---

None of which would be familiar to me.

OTOH I can't think of a situation where I missed this instruction. In a loop you could do the following:

LBL 0

*

...

u RCL A

GTO 0

*

If the first multiplication should turn out to be a problem you could add a 2nd label and jump to that:

GTO 1

LBL 0

*

LBL 1

...

u RCL A

GTO 0

*

We could probably better help you if you would tell us more precisely what you want to do.

Kind regards

Thomas

[Luiz C. Vieira (Brazil)]

Hi.

I saw the thread pointed by the link (just saw, could not understand neither translate) but there is a program listing like this one:

LBL B

ENTER

ENTER

*

MATRIX 1

uRCL C

*

X<->Y

RCL* C

+

RCL+ 9

RTN

In fact, the

uRCL C

is a recall with matrix C element pointer being moved forward to the next element after its execution (applies to STO as well). Simply activate the USER mode (make sure the USER indicator is lit) and press [RCL][C] while in program mode. You'll see

nnnu 45 13

in the LCD, where nnn is the step number. The upper ^u actually replaces the regular - signal, which is the indication that after this operation, the matrix element pointer will move forward (to the next element). You can check it by inspecting R00 and R01 contents.

Anyway, this does not apply to the RCL or STO arithmetic, though. If you need to enter the

RCL* C

simply press [RCL][×] [C] (the [×] is the multiplication key) and you'll see

nnn-45,20,13

in the LCD.

Hope this is what you are searching for.

Cheers.

Luiz (Brazil)

Edited: 29 Dec 2012, 6:16 p.m.