Difference between revisions of "2020 AMC 8 Problems/Problem 14"
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-franzliszt | -franzliszt | ||
+ | ==Solution 4== | ||
+ | we get that it is <math>4750</math> multiplied by <math>20</math>,solve and get <math>\boxed{\textbf{(D) } 95,000}</math> | ||
==Video Solution== | ==Video Solution== |
Revision as of 18:04, 19 November 2020
There are cities in the County of Newton. Their populations are shown in the bar chart below. The average population of all the cities is indicated by the horizontal dashed line. Which of the following is closest to the total population of all cities?
Diagram by sircalcsalot
Solution 1
The average is given to be . This is because the dotted line is halfway in between and . There are cities, so our answer is simply
Solution 2
We know that the average () of these group of numbers is the sum () divided by , so we can make the equation . Since the average is , we can solve for to get
~Pi_Pup
Solution 3
After reading the question, we notice that the dashed line is the average population of each city. Also, that dashed line is slightly less than . Since there are cities, the answer is slightly less than which is closest to .
-franzliszt
Solution 4
we get that it is multiplied by ,solve and get
Video Solution
~savannahsolver
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.