# How do you find the point c in the interval #-1<=x<=1# such that f(c) is equation to the average value of #f(x)=x^2-x#?

##### 1 Answer

Aug 1, 2017

Find the average value. Set the function equal to that value. Solve the equation in the interval.

#### Explanation:

Average value on

# = 1/2 [x^3/3-x^2/2]_-1^1#

# = 1/3#

Solve

# = 1/2 +- sqrt21/6#