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In the 67, if you use the charger without a good battery pack, it won't damage the processor or memory chips, but it apparently is possible for it to damage the custom read/write amplifier chip for the card reader. I'd recommend following the same rules as for the Woodstock series.
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Quote:
I don't believe that the power supply arrangement of the HP-67 is anything similar to the disasterous design of real Woodstock units. The Classic battery charger is used, which uses a three-conductor cable to deliver a feed to the electronics that comes from a regulated supply, and a separate circuit section for the battery charging function. The battery is separated from the electronics when the charger plug is pushed in.
True for all Classics except for the 67 and 65, in which the card reader is powered by 2 additional wires that are connected directly across the battery terminals. When the charger is plugged in, they are then connected to the charging circuit, not the logic circuit.
The charging circuit provides a constant 50 mA current to trickle charge the battery. But the voltage drop can be as high as 16 volts. As I understand it, the battery in effect forces a voltage drop of about 4V give or take. Without a battery, what would happen?
I suppose this was done because the charger logic supply cannot deliver the current needed by the card reader, but the battery can. Is this correct?
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Hello Mike,
Eric scooped my response by a few hours! The power I am concerned with in the HP-67 is directed to the card reader circuitry.
But in a more general sense, why subject your 30 year old collectable to any internal charging? Regardless of the family, I would charge all batteries outside the calculator and not stress the aging circuit at all, or subject it to a failing charger.
Cheers, Geoff