A simple puzzle (no prize offered :-)


Replace every # in the expression below with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 (used only once). If you find the correct order you'll obtain .577215664901, that is, the first 12 digits in the Euler-Mascheroni constant. The algebraic object should evaluate correctly on the HP-28/48/49/50, but you can use whatever calculator you like. Actually the approximation yields the constant in excess of about 2E-14, but due to rounding errors the result is not rounded up properly.



I looked for some approximations at MathWorld
but none would fit my purpose, so I created this one. It took me about two or three hours playing on the HP-32Sii and half an hour on the HP-200LX to find the expression, which makes me think the puzzle can be solved in less time just using a trial and error method. If you don't have this much time to waste, writing a short program might be a better solution.

Have fun!


P.S.: The final expression was found on 1/7/8, 06:59:23.4p.m. (local time). (if not true, a close approximation ;-)


I've got it - spoiler warning.

From right to left I have: 9365701284

- Pauli


I knew you'd solve it quickly. I should have posted it by midday (local-time), when you'd be sleeping :-)

Easier to solve than to make, isn't it?



I knew you'd solve it quickly. I should have posted it by midday (local-time), when you'd be sleeping :-)

Possibly. I've been at my computer for going on six hours now :-(

Easier to solve than to make, isn't it?

I'd think so. There are only 10! possible solutions but infinite possibilities in the setting.

- Pauli

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