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Post: #18
10-10-2007, 02:42 PM
How are you trying to enter such a complex number? I know you can press 3 i 4 and get that complex number on the stack, but what are you pressing to create a complex number using a variable or a constant? Give us a specific example of what keys you're pressing (or what equation you're trying) and that will help. ▼
Post: #19
10-10-2007, 03:05 PM
I wanted to try Euler's equation: e^(i(pi)) + 1 = 0 For the exponent if I enter "0 i 3.14" where I manually enter an estimate of pi, I'm OK If I enter "0 i shift pi" I am left with pi in the real portion of the number with no imaginary component and who know what in rectangular form in the Y register above it. This is very perplexing.
So I tried storing pi in the "a" register and tried: "0 i RCL a" and I get the same kind of nonsensical result. It sure is frustrating. Edited: 10 Oct 2007, 3:07 p.m. ▼
Post: #20
10-10-2007, 03:48 PM
The reason is because you cannot build complex numbers from values in registers or constants in the manner you are trying. You can see this in a program. In program mode, press EQN to turn on equation mode and type: RCL B then i then 2 Now leave program mode and single-step that program line. You get a syntax error.
Try the approach shown in the next posting. Edited: 10 Oct 2007, 4:07 p.m. after one or more responses were posted ▼
Post: #21
10-10-2007, 04:06 PM
Gene, Thanks for your thoughtful response even though it isn't what I wanted to hear! It's too bad a complex variable cannot be constructed from constants or a register - why should the calculator care where the number comes from? Oh well, on to the next problem like world peace or some such thing.
Cheers, ▼
Post: #23
10-10-2007, 04:10 PM
Egan, I will try your steps when I get home for there is where I left my HP35s. I will certainly let you know the outcome unless someone has a 35s with them now and can try your procedure.
Thanks,
Post: #24
10-10-2007, 10:31 PM
Ike -- Egan Ford's previous response is correct. The reason for the seemingly-inconsistent behavior is that hitting the pi key terminates data entry and pushes pi onto the stack. A previously-entered "i" then becomes a complete number, represented as "0i1" (0 + i1). Multiplying pi by "i" in either order produces the value you wanted. I have made detailed suggestions to HP's calculator team for improving the complex-number functionality, and will continue to follow up on them. Help may be on the way, if you're willing to wait a number of months. -- KS
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Post: #25
10-10-2007, 11:28 PM
Karl, Yes, Eagan is correct especially in the first solution. I had a bit more problem with the second but I'm not going to worry about it anymore. The bottom line is that now with the help from you folks I have something I can live with - thanks! Now get those HP folks in line!
Cheers! ▼
Post: #26
10-10-2007, 11:38 PM
For the 2nd: 1. Put a value in a register, e.g. AOr to make it easy: iBoth will build you a complex number from registers. For A+iB: number
Post: #27
10-11-2007, 10:06 PM
Karl - I'm numb with this stuff. Having solved all complex problems with the 42s why did HP need to reinvent the wheel? tm ▼
Post: #28
10-11-2007, 10:54 PM
Quote:
Two reasons: Dave.
Post: #31
10-12-2007, 01:04 AM
Hi, Trent --
Quote: Well, I can't fully concur on that point. I have yet to see a calculator from any manufacturer having ideal complex-number functionality, but certainly the HP-42S is among the best. Its display of complex numbers is perfect, but the HP-42S lacks the following:
Details will follow, hopefully within a week. Here's a sample: -- KS
Post: #32
10-11-2007, 01:10 AM
In mathematics, the square of imaginary unit i is -1. If I enter the imaginary number 0i1 and then take the square of it (x^2), the HP 35s displays "INVALID DATA." The same happens when I enter any complex number and take the square of it using the x^2 key on the calculator. If I enter the following, as shown in manual, p. 9-5:
1i1 The result is 0i2, since (1 + i)^2 = 1^2 + i + i + i^2 = 1 + 2i -1 = 0 + 2i So, in one way, the 35s does compute i^2. But just using x^2 will not work. If I enter:
i I get the result as -1i0 (or -1 + 0i). I originally thought the 35s did not compute i^2 at all, but it does. As noted in the manual, you can y^x to compute powers of a complex number. Cheers! David Bailey
Edited: 11 Oct 2007, 1:51 a.m. |