Using EQN, I have entered two equations:-(X+2)*(X-2)
and
X^2-4
Next, I input
3 STO X
EQN (then 'select' (X+2)*(X-2))
SOLVE X
And the output is X=2.0000I repeat the process with X^2-4 and get the same result.
Now, I input
-3 STO X
and repeat the above steps.
For (X+2)*(X-2) I get the result X=-2.0000 as expected.
But for X^2-4 I get X=2.0000.
I cannot seem to obtain X=-2.0000 as a root of X^2-4.Why is this?
Question about SOLVE on hp 35s
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Post: #2
08-04-2007, 07:30 AM
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Post: #5
08-04-2007, 09:35 AM
See example 2 in the 35s learning module "Formula solver part 2" found here:
Example 2 suggests the workaround.
Post: #6
08-04-2007, 09:20 AM
Tried your equation / SOLVE at HP-15C, which gives X= 2.0000 and X= -2.0000. Maybe the correct answer of HP35s is found in another register...
Edited: 4 Aug 2007, 10:21 a.m.
Post: #7
08-04-2007, 12:53 PM
Matt -- Here's the link to the thread in the Forum Archives: http://www.hpmuseum.org/cgi-sys/cgiwrap/hpmuseum/archv014.cgi?read=62665#62665 The link is my proposed solution (obviously not adopted); scroll to the top to find a very similar discussion for the HP-33S. It turns out that the "direct solution" logioc seems to have been lifted from the HP-17B/HP-27S from 1988; I didn't know that at the time. -- KS
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Post: #8
08-04-2007, 01:02 PM
And, again, I am still sorry for the shortness of that title back then in my response to you. :-) This "direct solve" approach is considered a feature. You don't take features away...anyone knows that. :-) Short answer: if you have a polynomial that is missing a term, add the term with a 0 coefficient. X^2-4=0 would be entered as x^2+0x-4=0. Then the solver will not try a direct solution. That is the way it is. |