Hi,

just to see what the best of you can do with their powerful brain and HP's, let me submit to you this little problem. (I apologize first for my poor english writing.)

"A bricklayer is working a the tenth floor af a building, without any lift in order of working at the moment. He is in a corridor, from which he needs to know the with, but he has forgotten his measuring tape in his car, and is too lazy to go to take it by feet...

Fortunately, he's noting that his 3 m long ladder and his 2 m long, placed "symetricaly" in the corridor (the bottom of one ladder at one side of the corridor, and the top of this ladder on the opposite wall, and the opposite for the other ladder), are crossing themselves at just 1 m of the floor (the length of his plumbline). He is thinking that it must be enough to calculate the witdh of the corridor, but he finds the problem difficult..."

Could someone here help him to find the solution (not graphicaly, of course...)

(I'm sorry, but I didn't manage to enclose any picture.)

Hope this will entertain you !

Regards from J.-M.