Around the HP65 HP67 era my boss had me calculate distances for his glider club. It was in the calculator book I was using, I shortened the program and made it automatic for crossing the equator. I have the manuals on CD and I request help finding that worked solution. If you could help me find the book and page please. Sam
Distance between geographic poimts


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03182007, 11:53 AM
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03182007, 03:12 PM
I have an HP42S program that computes Great Circle Distance here. Should be easy to adapt to the HP65 or HP67 or any other RPN scientific. dist = acos(cos(lat1)*cos(lat2)*cos(lon1lon2)+sin(lat1)*sin(lat2)) Where dist is an angle on the Great Circle passing through the two points. Assuming the calculator is in DEG mode, multiply by 60 to get nautical miles, etc. This formula works for any pair of coordinates  no issues with crossing the equator or passing over the poles or anything like that. UPDATE: There is more information, and more accurate formulae, here.  Thomas
00 { 101Byte Prgm } Edited: 18 Mar 2007, 5:07 p.m.
03182007, 06:00 PM
Hi, ▼
03182007, 10:13 PM
Thanks to all. I had hoped to find the example I used before but I will be more adventurous and try one of the complex solutions. Sam ▼
03182007, 11:27 PM
Are you referring to the programs in the Navigation Pacs for HP65 or HP67? Both of those manuals are on the DVD under the "Calculator Software Manuals" subheading. Les
03192007, 07:01 AM
I would recommend this highly. JeanMarc doesn't post nearly frequently enough on the Forum for my liking. I have become a huge fan of his workindeed, most of my more recent programming efforts in special functions for the HP33S and 32sii are basically shameless plagiarisations of his stuff. His contributions are prolific and are almost always huge improvements over what has previously been available in the HP41 users' library solution books. Can you let us know if you ever locate the old program you were thinking of? Les ▼
03192007, 09:04 AM
First my surprise at finding my own entry in this forum on Google search for Kinpo. Second the equation I used must have been in a calculator manual as I did not buy any other texts or programs.
03202007, 05:46 PM
Hi Les,
( sin(d/2) )^2 = ( sin(bb')/2 )^2 ( cos(LL')/2 )^2 where L , L' = longitudes and b , b' = latitudes
These formulas are less accurate than Andoyer's formulas,
Actually, d/2 is in Xregister at line 30 of the "TGD" program
Regards, 
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