The original charger for my HP19C had its calculator plug repaired (or better: rebuild) by the original owner. This new plug is build in order to secure a given polarity (a cut-out groove engages with the post between the two contact pins in the calculator), however, it appears that the charger output is AC (8VAC) - is there a reason for the chosen polarity. It appears that my spare charger (type 82066, 220V) with the original plug can be connected either way. Further, the original charger has an output of 3VA, the more recent one 2,5VA - is there a reason for this? Perhaps the latter, made in 1987, was intended primarily for the HP75.
Any comments would be appreciated.
Regards, Bo