Edited: 5 Feb 2013, 2:54 p.m. after one or more responses were posted
Record Mersenne Prime

02052013, 01:10 PM
02052013, 01:44 PM
Actually, that's 2^578851611, not 2^2578851611. The extra "2" makes quite a difference. Still quite a find!
02052013, 02:55 PM
Whoops! Corrected. Thanks Jim.
02052013, 06:24 PM
Drat! My HP19C was working on that one last month when it ran out of paper ;)
02062013, 09:24 AM
I have to out myself as an early SETI@homemember (I think I registered as user 6xx), having run the Mersenne program as well.
02062013, 11:54 AM
By their stats, those 100000 users have 730562 computers registered, so the picture is even uglier. Ouch is right.
02072013, 03:56 AM
Quote: Another simple word: Bollocks.
Regards.
02082013, 09:34 AM
Over 17 million digits  it would take a good number of years just for a human to write all the numbers of this number. Wow. It boggles the mind, just like we know of a million digits of pi.
02162013, 11:07 AM
Whenever M_n = 2^n1 is prime, the larger number P_n = (4^n  2^n)/2 is "perfect", i.e. its factors add up to the number itself. n=2: M_n = 3, P_n = 6 = 1 + 2 + 3 n=3: M_n = 7, P_n = 28 = 1 + 2 + 4 + 7 + 14 n=5: M_n = 31, P_n = 496 = 1 + 2 + 4 + 8 + 16 + 31 + 62 +124 + 248 This new Mercenne prime makes for a new perfect number.
At a rough guess, the number of digits in a Mercenne prime is approx 30% of n, and the number of digits in the corresponding perfect number is twice this, approx 60% of n. Edited: 16 Feb 2013, 11:08 a.m.
02162013, 07:33 PM
Quote:log(a^{n}) = n log(a) log(2) = 0.30103 ~ 30%
02182013, 03:55 AM
Quote:
After all, it's never been proved that there are none, so this is your chance to make math history ... XD
Best regards. 
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