The answer to question 1 was E. The early models did not have a lowered-ON key.
Question 2: In the spirit of guessing, how many full-precision real numbers can be stored in registers on the HP 35s?
No multiple choice this time.
Upcoming 35s question #2
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07-11-2007, 10:58 PM
The answer to question 1 was E. The early models did not have a lowered-ON key.
No multiple choice this time.
07-12-2007, 04:08 AM
Let me say, as much as can be represented by floating point numbers within the limits of the machine :^).
(I was right on q#1, I can afford to fail this time :-) Edited: 12 July 2007, 7:19 a.m.
07-12-2007, 09:26 AM
Answer is well over 2400 floating point, full precision numbers.
07-12-2007, 04:47 PM
That isn't exactly a precise answer to the question...
07-12-2007, 05:24 PM
Lol. Ok, 2514 is the actual, non-useful number. 801 x 3 + 26 x 3 + 6 x 3 + 5 x 3 which fills up all 801 indirect registers, all 26 lettered registers, all 6 stat registers (which have to be stored indirectly) and all 4 stack registers and lastx too. Reality is that you can now have indirect registers 1 through 800 filled with 3-D vectors containing 3 full precision real numbers using the program supplied in the learning module. That ought to do for now. :-)
07-12-2007, 05:24 PM
Indeed, my answer was way better. You just have to read the question the right way ;-). |
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