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promgramming??(built in func) - Harrington - 06-02-2004 This equation dosen't see to work well in my 49G+ I really don understand the underlaying factor for this what I do know is that other simple equations will work jus fine. The equation with the problem is : let assume 1/(x^2+3*x+2) I expect to see -1/(x+2) + (1)/(x+1) or vice versa.
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promgramming??(built in func) - V-PN - 06-03-2004 **NOTE ** Capitalization MUST be as shown ** Re: promgramming??(built in func) - bill platt - 06-03-2004 Hi VPN,
Re: promgramming??(built in func) - V-PN - 06-03-2004 Search for ALG48 in the www.hpcalc.org BYTES => #B61Ch 78 always??? - Harrington - 06-03-2004 please give some explination to this fragment. BYTES => #B61Ch 78. Look like an assemble code BYTES => #B61Ch 78 always??? - V-PN - 06-03-2004 1) RCL the program on stack level 1
Thanks VPN(never leave this board) - Harrington - 06-03-2004 you are helpful on this board thanks Help help help !!!!! please - Harrington - 06-04-2004 I see all the syntax my question is here : where should I type or key in this BYTEs=> ???Capitalization MUST be as shown ** How does BYTES => #B61Ch 78 slove this problem - Harrington - 06-04-2004 I get the memory location how does it slove the problem. why should I be worried about this location?
Re: How does BYTES => #B61Ch 78 slove this problem - Cameron - 06-05-2004 This isn't my bag, but... It doesn't *solve* the problem. It's not supposed to. And it's not a "memory location". I suspect that you've gone off on a tangent. It's not machine code; it's not tricky programming. It is simply a mechanism for confirming that you have keyed in VPN's program correctly.
The first number (#B61Ch) is a Try an experiment. VPN stressed that you must match the character case of his listing *exactly*. Re-key the program and change just one character. The program won't work (of course) but when you use BYTES you will get a *different* value to VPN's. That tells you that you made a mistake (although it doesn't show you what the mistake was). I hope that helped. Cameron PS: I know nothing of these new-fangled RPL calculators so I probably can't help you much more.
xyzzy Edited: 5 June 2004, 1:29 a.m.
I keyed in these correctly(1/(x^2+3*x+2)) - Harrington - 06-05-2004 what is interesting is that hp49G+ was programed under this condtion for built in function of this kind.n(x)/d(x) where n(x)=0 and d(x)=0 are true .cuz it work for any function of this kind x^2+3x+6/(x^3+3*4*x+8)
please help see if this work in ya calculator as well mine it is not while I'm posting this again.
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