So, it's time to change the batteries in my 17bii again, but I've reprogrammed more fantastic equations that I don't want to lose (like what happened to me the last time I changed the batteries). Does anyone know of a way to change the batteries in a 17bii without losing what you've stored in memory?

I looked for this topic in old threads, but didn't see where it had been discussed before.

Thanks in advance,

Brian

Brian,

take a look here:

http://www.hpmuseum.org/cgi-sys/cgiwrap/hpmuseum/archv018.cgi?read=137894#137894

Best regards,

Peter A. Gebhardt

Is memory loss normal with this particular model? I don't have this problem changing batteries on my Pioneers.

Have the new batteries out and ready to insert.

I put the case in my hand, then slip the calculator face down into it, about 3/4 of the way in.

I found that using a paperclip to remove the batteries works well: slide on end alongside the battery stack and gently pull out with slight pressure on the side.

Then slip the new batteries in immediately.

Hope this helps.

MikeO

Martin,

I've lost my elaborated equations two times before. To not get fooled a third time, I've used the described way and had no problems.

Although all pioneers "backup" the calculators memory by some sort of capacitor (as I learned later on, when bringing my problem to the attention of other forum members), I also wondered why especially my 17bII+ had these problems.

s/n: CNA42903649

Best regards

Peter A. Gebhardt

You may also try this link.

Regards,

Gerson.

Quote:

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I've lost my elaborated equations two times before.

s/n: CNA42903649

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I wonder if the problem is related to the first three characters of the serial number ...