A simple puzzle (no prize offered :-) - Printable Version +- HP Forums (https://archived.hpcalc.org/museumforum) +-- Forum: HP Museum Forums (https://archived.hpcalc.org/museumforum/forum-1.html) +--- Forum: Old HP Forum Archives (https://archived.hpcalc.org/museumforum/forum-2.html) +--- Thread: A simple puzzle (no prize offered :-) (/thread-130597.html) |
A simple puzzle (no prize offered :-) - Gerson W. Barbosa - 01-07-2008 Replace every # in the expression below with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 (used only once). If you find the correct order you'll obtain .577215664901, that is, the first 12 digits in the Euler-Mascheroni constant. The algebraic object should evaluate correctly on the HP-28/48/49/50, but you can use whatever calculator you like. Actually the approximation yields the constant in excess of about 2E-14, but due to rounding errors the result is not rounded up properly.
'(.#+EXP(-(EXP(EXP(.#)))))/LN(#)+##^(-#)*LN(#)-EXP(-(#^#/#))/e'
I looked for some approximations at MathWorld Have fun! Gerson.
P.S.: The final expression was found on 1/7/8, 06:59:23.4p.m. (local time). (if not true, a close approximation ;-)
Re: A simple puzzle (no prize offered :-) - Paul Dale - 01-07-2008 I've got it - spoiler warning. From right to left I have: 9365701284
- Pauli
Re: A simple puzzle (no prize offered :-) - Gerson W. Barbosa - 01-07-2008 I knew you'd solve it quickly. I should have posted it by midday (local-time), when you'd be sleeping :-) Easier to solve than to make, isn't it? Gerson.
Re: A simple puzzle (no prize offered :-) - Paul Dale - 01-07-2008 Quote: Possibly. I've been at my computer for going on six hours now :-(
Quote: I'd think so. There are only 10! possible solutions but infinite possibilities in the setting.
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