What would YOU call this? - Printable Version +- HP Forums (https://archived.hpcalc.org/museumforum) +-- Forum: HP Museum Forums (https://archived.hpcalc.org/museumforum/forum-1.html) +--- Forum: Old HP Forum Archives (https://archived.hpcalc.org/museumforum/forum-2.html) +--- Thread: What would YOU call this? (/thread-104520.html) |
What would YOU call this? - Chuck - 12-22-2006 Last week a few friends and I discussed this "function":
p.s. Stay out of the complex's. :)
Re: What would YOU call this? - Valentin Albillo - 12-22-2006 Hi, Chuck: I guess you want this:
f(x) = ln(1-x)+ln(x-2)
Best regards from V.
Re: What would YOU call this? - Chuck - 12-22-2006 Ahh, but your first step is not allowed; you have drastically changed the function. The original function f(x) = ln(1-x)+ln(x-2) Re: What would YOU call this? - John Gustaf Stebbins - 12-22-2006 Looking at a couple definitions of "function" I guess you could say that it is a function on the empty set, assuming you consider the empty set to be a valid domain. Doesn't seem proper, but I don't see where the laws of mathematics would fall apart.
Re: What would YOU call this? - Crawl - 12-23-2006 I'd call it a function, because "stay out of the complex" is an artifical human requirement, while analytic continuity is mathematically natural. I'd also say x / x = 1 at x = 0 (not that it's undefined), and 1 - 1 + 1 - 1 + 1 -... = 1/2, though. If you want to have a function that has no domain, why not define a function that really has no domain? Or at least something weirder than the logarithm, which is a perfectly normal function, except that it's multi-valued. How about f(x) = 1^x + 1^(2*x) + 1^(3*x) + 1^(4*x) + 1^(5*x) + ... which diverges to infinity for all x. Or even use something non-mathematical.
f(x) could take values, but since it's hard to establish if one number loves another, it might be undefined for all x.
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