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The answer to question 1 was E. The early models did not have a lowered-ON key.

Question 2: In the spirit of guessing, how many full-precision real numbers can be stored in registers on the HP 35s?

No multiple choice this time.

Let me say, as much as can be represented by floating point numbers within the limits of the machine :^).

(I was right on q#1, I can afford to fail this time :-)

Edited: 12 July 2007, 7:19 a.m.

Answer is well over 2400 floating point, full precision numbers.

That isn't exactly a precise answer to the question...

- Pauli

Lol. Ok,

2514 is the actual, non-useful number.

801 x 3 + 26 x 3 + 6 x 3 + 5 x 3

which fills up all 801 indirect registers, all 26 lettered registers, all 6 stat registers (which have to be stored indirectly) and all 4 stack registers and lastx too.

Reality is that you can now have indirect registers 1 through 800 filled with 3-D vectors containing 3 full precision real numbers using the program supplied in the learning module.

That ought to do for now. :-)

Indeed, my answer was way better. You just have to read the question the right way ;-).