HP Forums

Full Version: hp 15c - storage problem
You're currently viewing a stripped down version of our content. View the full version with proper formatting.

when i input a number and try to store it in any number other than "0" and "1", i get an "error 3" message. the hp tech support thought it might be a program storage issue, but that did not fix the problem. does anyone else have any experience with how to fix this problem?

thanks in advance for your help!

regards,

paul shirley
pshirley@gbbn.com

Hi,
On the HP-15C, only three registers are available
at all times, namely R0 and R1 (used for matrix operations)
and RI (used for some indirect operations).

The most likely cause for the rest of the registers
to be unavailable would be an improper memory allocation.

I suggest you try to reset the machine, by turning
it off, then press the minus (-) key and, without releasing
it, pressing the ON key and releasing both. This should
clear the machine and show "PR ERROR" on the display.

Then, try again to store anything in, say, R2. If
it doesn't work, maybe your machine needs service.

Hope it helps.

The suggestion given by our Ex-PPC Member is the one that would really get to the point. But if you want to keep data already stored in the calculator OR want to know how to resize memory partition, try it:

enter a numer from 0 to 64; this number will define how many registers you want beyond the thre pemanent ones;

press STO (i) ;

to check for it, press g MEM and keep the MEM key pressed; you should see a display like tis:

rr mm pp-b

were rr is the number you keyed in beforr pressing STO (i);
mm is the available memory for extended functions (complex stack, matrix, integration and root-finder) and pp is the number or registers containing programs, while b is the number of bytes available until next register.

Hi Luiz,

there must be a typo in your description. I believe it should be f DIM (i) with n in the x register.
n is the number of the highest available register. The default for n is 19 (RCL 0 to RCL .9)
RCL DIM (i) places the current n into the x register.

Gee, you´re completely right. I think it´s time to go back to the manuals before answering those questions. I tried placing the answer by heart, and I loose it.

Thanks, Achim, and forgive-me Paul.